86.3k views
5 votes
C(1) = 6, c(n) = c(n-1) - 16, find the 3rd term of the sequence.

A) -10
B) -16
C) 14
D) 18

User DeLac
by
7.3k points

1 Answer

4 votes

Final answer:

The 3rd term of the sequence is -26.

Step-by-step explanation:

The sequence is defined recursively with the formula c(n) = c(n-1) - 16. We are given that c(1) = 6. To find the 3rd term of the sequence, we can substitute the values of n into the formula. Starting with c(1) = 6, we can calculate c(2) = c(1) - 16 = 6 - 16 = -10. Continuing to c(3), we have c(3) = c(2) - 16 = -10 - 16 = -26. Therefore, the 3rd term of the sequence is -26.

User Danylo Gudz
by
7.1k points