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Label the points and the plane to show AB←→ ⊥ plane S, EC_ ≅ED_, and DB←→ intersecting plane S at point D.

User Lucamug
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Final answer:

To label a diagram with AB→ ⊥ plane S, EC_ ≅ ED_, and DB→ intersecting plane S at point D, draw plane S, mark AB perpendicular to it, indicate EC is congruent to ED with tick marks, and show the line DB intersecting the plane at point D.

Step-by-step explanation:

To label the points and the plane to show AB→ ⊥ plane S, EC_ ≅ ED_, and DB→ intersecting plane S at point D, follow these steps:

  1. Identify the points A, B, E, and D in a three-dimensional space.
  2. Draw a plane and label it as plane S.
  3. Sketch line AB to be perpendicular to plane S by using right angle marks where the line would intersect the plane. This would indicate that AB is orthogonal to plane S.
  4. Mark points E and D on the plane such that EC is congruent to ED, which you can show by marking these line segments with identical tick marks.
  5. Extend the line DB until it intersects plane S at point D, showing that DB is a line that intersects the plane.

By these actions, we have satisfied the requirement to show a line perpendicular to a plane, two congruent line segments on the plane, and another line intersecting the plane.

User Chris Putnam
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