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Sherman jumps off a high-diving platform with a horizontal velocity of 4.2 m/s and lands in the water 2.4 s later. How far from the base of the platform does he land?

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Final answer:

To calculate the distance Sherman lands from the base of the platform, multiply his horizontal velocity of 4.2 m/s by the time of 2.4 s in the air, resulting in 10.08 meters.

Step-by-step explanation:

The question asks how far from the base of the platform Sherman would land after jumping off a high-diving platform with an initial horizontal velocity of 4.2 m/s and taking 2.4 seconds before landing in the water. To find the horizontal distance (range) Sherman travels, we use the formula for horizontal motion: distance = velocity × time. Since there is no horizontal acceleration in this scenario, we can directly calculate the distance as:

distance = 4.2 m/s × 2.4 s

The answer comes out to be 10.08 meters. Thus, Sherman lands 10.08 meters away from the base of the high-diving platform.

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