Question

hello this is a trigonometry question hopefully you can help I did every thing else it's just the last one I can't get the reference angle for five in this question

Answer 1

1) Let's set a proportion to find 5 radians equivalence to degrees and then locate which quadrant

`\begin{gathered} \theta=5 \\ \pi-----180\circ \\ 5------x \\ \\ x=\frac{5\text{ x 180}}{\pi} \\ x=286.5\text{ or }(900)/(\pi) \\ \end{gathered}`

So since Quadrant IV is >270º and < 360º.

θ is in Quadrant IV

2) Let's find the Reference angle

Since the angle is in Quadrant IV, we subtract from 360º (or 2pi)

360º-286.5=73.5º

or

`2\pi-(900)/(\pi)=(2\pi-900)/(\pi)`