188k views
3 votes
5/6 of the population in Town A is NOT Swedish. In addition, 2/3 of the Swedish population in Town A is male. A random person from Town A is selected.What is the probability that a randomly selected person from Town A is both Swedish and female?

A. 1/9
B. 1/12
C. 1/18
D. 10/18
E. 11/6

User Surendher
by
7.7k points

1 Answer

2 votes

Final answer:

The probability that a randomly selected person from Town A is both Swedish and female is 1/18, by multiplying the fractions of the Swedish population and the fraction of females within the Swedish population.

Step-by-step explanation:

To find the probability that a randomly selected person from Town A is both Swedish and female, we need to use the probability rules. Since 5/6 of the population are not Swedish, 1/6 of the population is Swedish. We are given that 2/3 of the Swedish population is male, which implies that 1/3 of the Swedish population is female.

Firstly, calculate the proportion of the Swedish population to the total population: 1/6. Secondly, out of the Swedish population, calculate the proportion of females: 1/3. To find the combined probability of two independent events, we multiply their individual probabilities. Thus, the probability of a randomly selected person being both Swedish and female is (1/6) * (1/3) = 1/18.

Therefore, the answer is: C. 1/18.

User Alan Scarpa
by
8.1k points