Final answer:
Yes, on the interval -5 ≤ x ≤ 3, there must be a value of x for which f(x) = 30.
Step-by-step explanation:
Yes, on the interval -5 ≤ x ≤ 3, there must be a value of x for which f(x) = 30. Since the given interval includes both -5 and 3, it covers a range of x values. If we take a look at the function f(x) = 30, we can see that it represents a horizontal line with a constant value of 30. This means that at any point on the interval -5 to 3, the y-value (which is f(x)) will be equal to 30. Therefore, there must be a value of x within this interval for which f(x) is equal to 30.