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A gas-tight vessel is filled with air at 27 degrees C and 1.00 atm. Assuming air to be 79% N and 21% O2 (by vol) calculate...

A) partial pressure of N2
a. 0.79 atm
b. 0.21 atm
c. 0.27 atm
d. 0.73 atm
B) partial pressure of O2
a. 0.21 atm
b. 0.79 atm
c. 0.73 atm
d. 0.27 atm

1 Answer

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Final answer:

Using Dalton's Law, the partial pressure of nitrogen (N₂) in the vessel is 0.79 atm, and the partial pressure of oxygen (O₂) is 0.21 atm.

Step-by-step explanation:

The partial pressure of a gas in a mixture can be found using Dalton's Law of Partial Pressures, which states that the total pressure exerted by a gas mixture is the sum of the partial pressures of each individual component gas. These partial pressures are directly proportional to the percentage composition of each gas.

For nitrogen (N₂), which makes up 79% of the air by volume, the partial pressure can be calculated as follows:

Partial pressure of N₂ = Total pressure × Percentage of N₂
= 1.00 atm × 0.79
= 0.79 atm

Therefore, the partial pressure of N₂ is 0.79 atm.

Similarly, for oxygen (O₂), which makes up 21% of the air by volume, the partial pressure is:

Partial pressure of O₂ = Total pressure × Percentage of O₂
= 1.00 atm × 0.21
= 0.21 atm

The partial pressure of O₂ in the air-filled vessel is 0.21 atm.

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