Final answer:
The initial horizontal velocity of a high jumper with an initial velocity of 10 m/s at an angle of 15° is calculated using the cosine component of the initial velocity, yielding the answer d. 10 cos(15°) m/s.
Step-by-step explanation:
The student is asked to calculate the initial horizontal velocity of a high jumper who leaves the ground with an initial velocity of 10 m/s at an angle of 15°. The initial horizontal velocity can be calculated using the cosine component of the initial velocity vector. The formula to find the horizontal component (vx) is vx = v * cos(θ), where v is the initial velocity and θ is the angle of projection relative to the horizontal.
Now, applying the formula to the given values:
vx = 10 m/s * cos(15°)
Upon calculating, we find that the correct answer is d. 10 cos(15°) m/s, which will provide the high jumper's initial horizontal velocity.