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21x² +10√3 xy + 31y² =144 Sketch the graph.

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Final answer:

To sketch the graph of the equation 21x² + 10√3xy + 31y² = 144, we need to identify the type of curve it represents. This equation is a quadratic equation in two variables x and y, and it represents a conic section known as an ellipse. To sketch the graph, we can use the properties of ellipses.

Step-by-step explanation:

To sketch the graph of the equation 21x² + 10√3xy + 31y² = 144, we need to identify the type of curve it represents. This equation is a quadratic equation in two variables x and y, and it represents a conic section known as an ellipse. To sketch the graph, we can use the properties of ellipses.

  1. First, rewrite the given equation in standard form by completing the square for x and y.
  2. Then, determine the center, length of major and minor axes, and the eccentricity of the ellipse.
  3. Finally, plot the center, axes, and sketch the ellipse accordingly.

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