Final answer:
The tension T1 in one of the ropes holding the 1 kg container suspended at an angle of 30° is 9.81 N, which is equal to the weight of the container.
Step-by-step explanation:
The value of the tension T1 for a 1 kg container suspended by two ropes at an angle of 30° can be found using the equilibrium condition and Newton's second law. Ignoring the mass of the ropes, we can say the container is in static equilibrium, so the upward force (tensions) must be equal to the downward force (gravity). The weight of the container (W) is given by its mass (m) times the gravitational acceleration (g): W = mg = (1 kg)(9.81 m/s²) = 9.81 N. The vertical component of T1 will be T1 sin(θ), and since θ is 30°, this becomes T1 sin(30°) = T1(1/2). Therefore, if both ropes are identical and have the same tension, T1 will be double the weight divided by 2, which is 9.81 N; thus T1 = 9.81 N.