Question

What is the molarity of a NaCl solution that contains 142.9 g of NaCl in 1100 ml of solution? (Molar mass NaCl: 58.5g/mol)

A) 1.23 M
B) 2.13 M
C) 2.45 M
D) 3.00 M

Answer 1

The molarity of the NaCl solution is 2.22 M.

Step-by-step explanation:

The molarity of a solution is calculated by dividing the number of moles of solute by the volume of the solution in liters. In this case, we need to convert the mass of NaCl to moles using the molar mass. The molar mass of NaCl is 58.5 g/mol, so 142.9 g of NaCl is equal to 2.44 mol.

Next, we need to convert the volume of the solution to liters. Since 1 L is equal to 1000 mL, 1100 mL of solution is equal to 1.1 L.

Finally, we divide the number of moles of NaCl by the volume of the solution in liters to calculate the molarity:

Molarity = moles of NaCl / volume of solution (in L)

Molarity = 2.44 mol / 1.1 L = 2.22 M