Final answer:
The force applied down the ramp to a 10 kg object on a 30° incline is 49 Newtons. This is the component of the gravitational force acting parallel to the surface of the ramp.
Step-by-step explanation:
The student's question is asking about the force applied to an object with a certain mass that is positioned on an incline or ramp. Here, we are dealing with a 10 kg object on a 30° incline. To solve this problem, we can use the component of the gravitational force acting along the ramp, which is given by F = m · g · sin(θ), where m is the mass, g is the acceleration due to gravity (9.8 m/s²), and θ is the angle of the incline.
To calculate the force, we substitute the given values: F = 10 kg · 9.8 m/s² · sin(30°). Since sin(30°) is 0.5, the force comes out to be F = 10 · 9.8 · 0.5 = 49 N.
The force applied down the ramp due to gravity for the object with a mass of 10 kg is therefore 49 Newtons.