Final answer:
The zeros of the equation y = x^2 + 2x - 8 are -4 and 2.
Step-by-step explanation:
The zeros of the quadratic equation y = x^2 + 2x - 8 can be found by setting the equation equal to zero:
x^2 + 2x - 8 = 0
Next, we can factor this equation or use the quadratic formula to find the zeros. In this case, the quadratic formula is:
x = (-b ± √(b^2 - 4ac))/2a
Plugging in the values for a, b, and c from the equation, we get:
x = ( -2 ± √(2^2 - 4(1)(-8)))/2(1)
Simplifying further:
x = (-2 ± √(4 + 32))/2
x = (-2 ± √36)/2
x = (-2 ± 6)/2
Therefore, the zeros of the equation are x = -4 and x = 2. So, the correct answer is option A: -4, 2.