Question

. A tank contains 2500 L of argon gas. The pressure is13790 kPa and the temperature is 25ºC. How many moles of argon are in the tank?

Answer 1

There are 13,917.2 moles of argon.

Step-by-step explanation:

1st) The given information from the exercise is:

- Volume (V): 2500L

- Pressure (P): 13790kPa

- Temperature (T): 25°C

It is important to conver all the variables units to liters, atm and Kelvin:

- Conversion from kPa to atm:

`13790kPa*(0.00987atm)/(1kPa)=136.11atm`

- Conversion from °C to K:

`25+273.15=298.15K`

2nd) Now we can replace the values of pressure, volume and temperature in the Ideal Gases formula to calculate the number of moles:

`\begin{gathered} P*V=n*R*T \\ 136.11atm*2500L=n*0.082(atm*L)/(mol*K)*298.15K \\ 340,275atm*L=n*24.45(atm*L)/(mol) \\ (340,275atm*L)/(24.45(atm*L)/(mol))=n \\ 13,917.2mol=n \end{gathered}`

Finally, there are 13,917.2 moles of argon.