Question

An object is moving at a constant velocity of v=5 m/s. If the object is at x=−12 m at t=2 s, what was the object's position at t=0s?

a) x=−2 m

b) x=−7 m

c) x=−22 m

d) x=0 m

Answer 1

Answer:d

Step-by-step explanation:

Answer 2

Using the formula for constant velocity motion, we calculate the initial position (x_0) of the object by subtracting the product of velocity and time from the known position at t=2s. The object's position at t=0s was x=-22 m.

Step-by-step explanation:

To find the object's position at t=0s when it is moving at a constant velocity of v=5 m/s and knowing the position at t=2s is x=-12 m, we use the formula for constant velocity motion:

x = x_0 + vt

Where:

• x_0 is the initial position at t=0s
• v is the velocity (5 m/s)
• t is the time (2s for which the position is known)
• x is the position at time t (given as -12m at t=2s)

Rearranging this formula to solve for x_0:

x_0 = x - vt

Substituting the given values, we have:

x_0 = (-12 m) - (5 m/s)(2 s)

x_0 = -12 m - 10 m

x_0 = -22 m

Therefore, the object's position at t=0s was x=-22 m.