Question

Divide 4c/3b​ by 2c^3/9bc​. Simplify your answer as much as possible.

a) 6b^2

b) 6/c^2

c) 9/2c^2​

d) 2/9b^2

Answer 1

Dividing the fraction 4c/3b by 2c^3/9bc and simplifying the result gives the simplified form 6/c^2.

Step-by-step explanation:

To divide the fraction 4c/3b by the fraction 2c^3/9bc, you need to multiply the first fraction by the reciprocal of the second. The reciprocal of 2c^3/9bc is 9bc/2c^3. Multiplying these together, you get:

(4c/3b) × (9bc/2c^3) = (4 × 9b × c × c)/(3b × 2c^3)

Now, simplify by canceling out common factors. You can cancel one c from the numerator and denominator, and cancel b from both as well:

(4 × 9)/(3< × 2c^2)

This simplifies to:

36/6c^2 = 6/c^2

Therefore, the simplified form of dividing the fraction 4c/3b by 2c^3/9bc is 6/c^2.