Question

A student requires 2.00L of 0.100M NH₄NO₃ from a 1.75 M solution. What volume of the 1.75 M solution should the student use?

a) 2.29 L
b) 2.86 L
c) 1.14 L
d) 1.60 L

Answer 1

The student should use 114.3 mL of the 1.75 M NH₄NO₃ solution to prepare 2.00 L of a 0.100 M solution.

Step-by-step explanation:

To determine the volume of a 1.75 M NH₄NO₃ solution needed to make 2.00 L of a 0.100 M NH₄NO₃ solution, we can use the dilution formula M1V1 = M2V2 where:

• M1 is the molarity of the initial concentrated solution.
• V1 is the volume of the initial concentrated solution needed.
• M2 is the molarity of the final diluted solution.
• V2 is the volume of the final diluted solution.

Plugging in the given values:

M1V1 = M2V2
1.75 M × V1 = 0.100 M × 2.00 L
V1 = (0.100 M × 2.00 L) / 1.75 M
V1 = 0.200 L / 1.75
V1 = 0.1143 L, which is 114.3 mL

Therefore, the student should use 114.3 mL of the 1.75 M NH₄NO₃ solution to make 2.00 L of a 0.100 M solution.