Question

Draw the graph of the polynomial p(x) = x² + 2x - 3 and find the zeroes of the polynomial from the graph.

Answer 1

`p(x)=x^2+2x-3`

The zeroes of p(x) are given by:

`\begin{gathered} x=(-2\pm√(2^2-4\cdot(-3)))/(2) \\ x_=(-2\pm4)/(2) \\ x_+=-3 \\ x_-=1 \end{gathered}`

The vertex of the polynomial is given by:

`(-(b)/(2a),-((b^2-4ac))/(4a))=(-1,-4)`

The y-intercept is (0,-3)

Therefore, we can graph the polynomial tracing a parabola passing through (-3,0), (-1,-4), (0,-3) and (1,0):