Final answer:
The question asks for the magnitude and direction of a second displacement for a bicyclist, which involves vector addition and trigonometry in physics. By breaking displacements into components and applying the Pythagorean theorem, you can find the resultant displacement.
Step-by-step explanation:
The problem you've presented involves finding the magnitude and direction of a second displacement for bicycle 2 so that it will end in the same location as bicycle 1, given the first displacement of bicycle 1 and bicycle 2. This is a physics problem that involves vector addition and trigonometry to solve for the resultant displacement vector.
To solve problems like this, you would typically break each displacement into its north-south and east-west components, sum these components separately, and then use the Pythagorean theorem and trigonometry to find the resultant displacement and direction.
As an example unrelated to the initial question, if a cyclist rides 3 km west (negative displacement in the east-west direction) and then turns around and rides 2 km east, their displacement would be -1 km (since east is positive and west is negative), and their total distance traveled would be 5 km. The magnitude of the displacement is the absolute value of the displacement, so it would be 1 km regardless of direction.