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Given the equation 3y+4x=16, find the slope and y-intercept of the line.

a) Slope: −4/3, Y-Intercept: 4
a) Slope: 4/3, Y-Intercept: -4
a) Slope: 3/4, Y-Intercept: 16
a) Slope: −3/4, Y-Intercept: -16

1 Answer

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Final answer:

The slope of the line is -4/3 and the y-intercept is 16/3.

Step-by-step explanation:

To find the slope and y-intercept of the line represented by the equation 3y+4x=16, we need to rewrite the equation in slope-intercept form, which is y=mx+b. Here, m represents the slope and b represents the y-intercept.

Start by isolating y on one side of the equation:

3y = -4x + 16

Divide both sides of the equation by 3:

y = (-4/3)x + 16/3

So, the slope of the line is -4/3 and the y-intercept is 16/3.

We now see that the slope (m) is -4/3 and the y-intercept (b) is 16/3, which is approximately 5.33, not an integer as presented in the options. Therefore, the correct slope is -4/3, and the y-intercept is 16/3.

It is important to note that the options provided do not include the correct y-intercept value found in the calculation, which is 16/3, not an integer value.

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