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Find an equation for the line with the given properties. Express your answer using either the general form or the slope-intercept form of the equation of a line.Parallel to the line y=5x containing the points (-5,5)

User Rfrittelli
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1 Answer

14 votes
14 votes

To answer this question we will use the following slope-point formula for the equation of a line:


y-y_1=m(x-x_1)\text{.}

Recall that two lines are parallel if they have the same slope.

Now, notice that the given equation is y=5x, therefore, the slope of the given equation is 5.

Using the slope-point formula, we get that the equation of the parallel line to y=5x that passes through (-5,5) is:


y-5=5(x-(-5))\text{.}

Simplifying the above equation we get:


\begin{gathered} y-5=5(x+5), \\ y-5=5x+25. \end{gathered}

Adding 5 to the above equation we get:


\begin{gathered} y-5+5=5x+25+5, \\ y=5x+30. \end{gathered}

Answer:


y=5x+30.

User Argeny
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