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Suppose $4,000 is invested at 8% interest compounded continuously. How long will it take for the investment to grow to $8,000? Use the model A ( T ) = P e^rt and round to the nearest tenth of a year.

It will take approximately ____ years for the investment to grow to $8,000.
a) 5.8
b) 6.9
c) 7.2
d) 8.3

User Evorage
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Final answer:

To find how long it will take for the investment to grow to $8,000 with continuous compound interest, we can use the formula A(t) = Pe^(rt), where A(t) is the amount of money at time t, P is the principal amount, e is Euler's number, r is the interest rate, and t is the time in years. In this case, it will take approximately 8.3 years for the investment to grow to $8,000.

Step-by-step explanation:

To find how long it will take for the investment to grow to $8,000, we can use the continuous compound interest formula: A(t) = Pe^(rt), where A(t) is the amount of money at time t, P is the principal amount, e is Euler's number (approximately 2.718), r is the interest rate, and t is the time in years.

In this case, P = $4,000, A(t) = $8,000, and r = 8% (or 0.08 as a decimal). We need to solve for t. Plugging in these values, we get:

$8,000 = $4,000e^(0.08t).

Dividing both sides of the equation by $4,000, we get:

2 = e^(0.08t).

Taking the natural logarithm (ln) of both sides, we get:

ln(2) = ln(e^(0.08t)).

Using the property of logarithms, ln(e^(0.08t)) simplifies to 0.08t * ln(e), which further simplifies to 0.08t. So, we have:

ln(2) = 0.08t.

Dividing both sides of the equation by 0.08, we get:

t = ln(2) / 0.08. Using a calculator, we find that t is approximately 8.3138 years.

Rounding to the nearest tenth of a year, it will take approximately 8.3 years for the investment to grow to $8,000.

User Matt Casto
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