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What is the memory size (in bytes) if the address is 24 bits and the Word size is 16 bits?

a) 64 MB
b) 128 KB
c) 128 MB
d) 64 KB

1 Answer

4 votes

Final answer:

The memory size is 256 bytes.

Step-by-step explanation:

The memory size can be calculated by the formula 2^(address width - word width).



Given the address width is 24 bits and the word width is 16 bits, we have:



Memory size = 2^(24 - 16) = 2^8 = 256 bytes



Since the question is asking for the memory size in bytes and none of the options match 256 bytes, none of the given options are correct.

User FernandoH
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