Question

Given the reaction: CaCN2+3H2O=CaCO3+2NH3CaCN2+3H2O=CaCO3+2NH3

Calculate the amount of
CaCO3CaCO3produced if 47.5 moles of NH3NH3are produced.

Answer 1

To find the amount of CaCO3 produced from 47.5 moles of NH3, we use the 1:2 stoichiometric ratio from the reaction CaCN2 + 3H2O → CaCO3 + 2NH3. Since one mole of CaCN2 yields two moles of NH3, 47.5 moles of NH3 will come from 23.75 moles of CaCN2. Consequently, 23.75 moles of CaCO3 will be produced.

Step-by-step explanation:

To calculate the amount of CaCO3 produced when 47.5 moles of NH3 are produced, we will use the stoichiometry of the given chemical reaction:

CaCN2 + 3H2O → CaCO3 + 2NH3

The stoichiometry of the reaction shows that one mole of CaCN2 produces one mole of CaCO3 and two moles of NH3. Therefore, we can write the stoichiometric relationship as follows:

• 1 mole of CaCN2 → 2 moles of NH3
• 1 mole of CaCN2 → 1 mole of CaCO3

To find the moles of CaCO3 produced, we divide the moles of NH3 produced by the ratio of NH3 to CaCO3 from the balanced equation, which is 2:1.

1. Calculate the moles of CaCN2 needed to produce 47.5 moles of NH3: (47.5 moles NH3) ÷ (2 moles NH3/1 mole CaCN2) = 23.75 moles of CaCN2.
2. Since the ratio of CaCN2 to CaCO3 is 1:1, the moles of CaCO3 formed will be the same as the moles of CaCN2 required, which is 23.75 moles of CaCO3.

Therefore, 23.75 moles of CaCO3 are produced when 47.5 moles of NH3 are produced.