145k views
2 votes
F(x)=x^3+2x^2-x^-^2
plot the x and y intercepts of the function

User Pontus
by
7.9k points

1 Answer

2 votes

Final Answer:

To find the x-intercepts, set f(x) = x³ + 2x² - x - 2 equal to zero and solve for x and to find the y-intercept, set x to zero. The x-intercepts are (-1, 0), (1, 0), (-2, 0), and the y-intercept is (0, -2).

Step-by-step explanation:

To find the x-intercepts, set f(x) equal to zero and solve for x:

x³ + 2x² - x - 2 = 0

You can try factoring or use numerical methods like the rational root theorem or synthetic division. Factoring, you find that x = -1 is a root. Therefore, (x + 1) is a factor:

(x + 1)(x² + x - 2) = 0

Now, factor the quadratic part:

(x + 1)(x - 1)(x + 2) = 0

So, the x-intercepts are x = -1, 1, -2.

To find the y-intercept, set x to zero:

f(0) = 0³ + 2 · 0² - 0 - 2 = -2

Therefore, the y-intercept is (0, -2) .

So, the x-intercepts are (-1, 0), (1, 0), (-2, 0), and the y-intercept is (0, -2).

Complete Question:

f(x) = x³ + 2x² - x - 2

plot the x and y intercepts of the function

User Covati
by
7.9k points