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What is the perimeter of the polygon with vertices Q(-3,2), R(1,2), S(1,-2), T(-3,-2)?

a. 8 units
b. 12 units
c. 16 units
d. 20 units

User Gracelynn
by
7.6k points

1 Answer

4 votes

Final answer:

To find the perimeter of the polygon, we can use the distance formula to calculate the length of each side and then add up all the side lengths. The perimeter of the polygon with vertices Q(-3,2), R(1,2), S(1,-2), T(-3,-2) is 12 units.

Step-by-step explanation:

To find the perimeter of the polygon, we need to add up the lengths of all the sides. We can use the distance formula to calculate the length of each side. Let's calculate the length of QR first:

DQR = sqrt((1-(-3))^2 + (2-2)^2) = sqrt(16) = 4 units

Next, let's calculate the length of RS:

DRS = sqrt((1-1)^2 + (-2-2)^2) = sqrt(16) = 4 units

Now, let's calculate the length of ST:

DST = sqrt((-3-1)^2 + (-2-2)^2) = sqrt(16) = 4 units

Finally, let's calculate the length of TQ:

DTQ = sqrt((-3-(-3))^2 + (-2-2)^2) = sqrt(0) = 0 units

Adding up the lengths of all the sides, we get:

Perimeter = QR + RS + ST + TQ = 4 + 4 + 4 + 0 = 12 units