Question

Keiko, Sam, and Aldo have a total of $105 in their wallets. Sam has 4 × what Aldo has, Keiko has $9 less than Aldo. How much does each have?

a. Amount in Keiko's wallet: $6.50
b. Amount in Sam's wallet: $26
c. Amount in Aldo's wallet: $17
d. Amount in Keiko's wallet: $9
e. Amount in Sam's wallet: $31
f. Amount in Aldo's wallet: $21

Answer 1

Keiko has $10, Sam has $76, and Aldo has $19.

Step-by-step explanation:

Let's solve the problem step by step:

Let's represent the amount in Aldo's wallet as 'x'.

According to the given information, Sam has 4 times what Aldo has. So, Sam has 4 * x = 4x.

Keiko has $9 less than Aldo, so Keiko has x - $9.

Now we can set up an equation: x + 4x + (x - $9) = $105.

Simplifying the equation, we get: 6x - $9 = $105.

Adding $9 to both sides of the equation, we have: 6x = $114.

Dividing both sides by 6, we get: x = $19.

So, Aldo has $19, Sam has 4 * $19 = $76, and Keiko has $19 - $9 = $10.

Therefore, a. Amount in Keiko's wallet: $10, b. Amount in Sam's wallet: $76, and c. Amount in Aldo's wallet: $19.