Question

The conductivity of a 0.20 M solution of KCl at 298 K is 0.25 cm⁻¹. Calculate molar conductivity.

a. 0.50 S mol⁻¹ cm²
b. 1.25 S mol⁻¹ cm²
c. 0.125 S mol⁻¹ cm²
d. 0.20 S mol⁻¹ cm²

Answer 1

The correct answer for the molar conductivity of a 0.20 M solution of KCl with a conductivity of 0.25 cm⁻¹ at 298 K is 1.25 S mol⁻¹ cm².

Step-by-step explanation:

To calculate the molar conductivity of a 0.20 M solution of KCl with a conductivity of 0.25 cm⁻¹ at 298 K, we use the equation:

λₘ = κ / C

where λₘ is the molar conductivity, κ is the conductivity, and C is the concentration in moles per liter (M). Substituting the given values:

λₘ = 0.25 cm⁻¹ / 0.20 M

λₘ = 1.25 S cm² mol⁻¹

Therefore, the correct answer is b. 1.25 S mol⁻¹ cm².