Final answer:
Using the normal distribution and Z-scores for a class with a mean weight of 103 pounds and a standard deviation of 6.3 pounds, a student in the lowest 2.5% weighs approximately 90.4 pounds.
Step-by-step explanation:
If a student's weight is in the lowest 2.5% of the class, we need to use the normal distribution and Z-scores to find this value. Given that the mean weight is 103 pounds and the standard deviation is 6.3 pounds, we look for the Z-score that corresponds to the percentile of 2.5%. This Z-score is approximately -1.96 because it falls 1.96 standard deviations below the mean on a normal distribution.
We can then use the Z-score formula:
- Z = (X - mean) / standard deviation
- -1.96 = (X - 103) / 6.3
- X = -1.96 * 6.3 + 103
- X ≈ 90.4 pounds
Thus, a student who weighs in the lowest 2.5% of the class would weigh approximately 90.4 pounds, which corresponds to option d).