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How many observations should a time study analyst plan for in an operation that has a standard deviation of 2.6 minutes per piece? The goal is to estimate the mean time per plece to within 1.1 minutes, with a confidence of 95.5 percent. (Do not round intermediate calculations. Round up your final answer to the next whole number.)

Number of observations ____

User Mabalenk
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Final answer:

To estimate the mean time per piece to within 1.1 minutes with a 95.5% confidence level, a time study analyst should plan for 23 observations, rounded up from the calculated sample size of 22.36.

Step-by-step explanation:

To calculate the number of observations a time study analyst should plan for in order to estimate the mean time per piece to within a certain margin of error with a specified confidence level, the formula for the sample size n when estimating a mean can be used:

n = (z * σ / E)^2

Where:

  • z is the z-score corresponding to the desired confidence level
  • σ (sigma) is the population standard deviation
  • E is the desired margin of error

Given that the standard deviation σ is 2.6 minutes, the desired margin of error E is 1.1 minutes, and the desired confidence level is 95.5 percent (which corresponds to a z-score of approximately 2 for the normal distribution), we can plug these values into the formula:

n = (2 * 2.6 / 1.1)^2

Calculating this gives us n = (5.2 / 1.1)^2 ≈ 22.36. Since we cannot have a fraction of an observation, we round up to the next whole number, which gives us 23 observations needed.

User Robert Wilkinson
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