Question

The standard form of a square root function is f(x) = sqrt x - h + k. For the function f(x) = sqrt x+ 2 + 1. set (x - h) = 0 and solve for x. Also, what is the value of k? What was the starting point, again?

Answer 1

we are given the following standard form of a function:

`f(x)=\sqrt[]{x-h}+k`

We are also given the following function:

`f(x)=\sqrt[]{x+2}+1`

since "x - h" is the term under the radical, we have:

`x-h=x+2`

setting this value to zero, we get:

`x+2=0`

To solve for "x" we will subtract 2 to both sides:

`\begin{gathered} x+2-2=-2 \\ x=-2 \end{gathered}`

"k" is the value we add to the radical, therefore:

`k=1`

The starting point is:

`(h,k)=(-2,1)`

That is, up one, right two.