Question

From the values you determined in 4) d. and 5), if you were to charge the capacitor, how long would it take before its voltage would drop to less than 1% of its original value?

Answer 1

To determine the time it takes for a capacitor's voltage to drop to less than 1% of its original value, calculate the time constant using the resistance and capacitance values. Then, use the exponential decay equation to find the time.

Step-by-step explanation:

To determine how long it takes for the voltage on a capacitor to drop to less than 1% of its original value, we need to calculate the time constant and then use it in the exponential decay equation.

The time constant (t) is given by the product of the resistance (R) and the capacitance (C), so t = RC.

Once we have the time constant, we can use the equation V(t) = Vo * e^(-t/RC) to find the time it takes for the voltage to decrease to less than 1% of its original value.

For example, if the time constant is 5 seconds, it would take approximately 5 * 5 = 25 seconds for the voltage to drop to less than 1% of its original value.