Question

A splitter is a device that has a single input and several outputs. It is used to send a signal to several different locations. For example, your apartment or house might have cable TV that delivers a wideband signal via a coaxial cable. A splitter can be used to send the same signal to different rooms so that individual TV sets can receive all the programs and channels that are available from the cable TV company. This problem is about a splitter with three outputs. A broadband signal with analog TV signals from 50MHz to 600MHz is connected to the input of the splitter. At a channel frequency of 50MHz the input power is −20dBm. The output power at each of the three splitter output terminals is −27dBm.

What is the power at the splitter input in mW ?

Answer 1

The power at the splitter input at a frequency of 50MHz with an input power of −20 dBm is 0.01 milliwatts (mW).

Step-by-step explanation:

The power at the splitter input in mW can be found by converting the input power from decibels to milliwatts. The equation for this conversion is P(mW) = 1 mW * 10^(P(dBm)/10), where P(dBm) is the power in dBm. Since the input power is −20 dBm at 50MHz, the power in mW can be calculated as follows:

P(mW) = 1 mW * 10^(−20/10) = 1 mW * 10^(−22) = 1 mW * 10^(−2) = 0.01 mW.

Therefore, the power at the splitter input is 0.01 mW.