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A 1/4-hp, 110-V, 60-Hz, four-pole, capacitor-start motor has the following equivalent circuit parameter values in 2) and losses:

R₁,ₘₐᵢₙ = 2.02
X₁,ₘₐᵢₙ = 2.79
R₂,ₘₐᵢₙ = 4.12
X₂,ₘₐᵢₙ = 2.12
Xₘ,ₘₐᵢₙ = 66.8
Core loss = 24 W
Friction and windage loss = 13 W

For a slip of 0.05, determine the stator current, power factor, power output, speed, torque, and efficiency when this motor is running as a single-phase motor at rated voltage and frequency with its starting winding open.

User Waterlink
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Final answer:

The question requires analysis of a four-pole, capacitor-start motor with its starting winding open and calculations of various performance parameters based on the given equivalent circuit parameters and losses at a specific slip condition.

Step-by-step explanation:

The student is asking about the performance characteristics of a four-pole, capacitor-start motor with the starting winding open under a specified slip condition. Given the equivalent circuit parameters, core loss, friction, and windage loss for the motor, the following can be calculated: stator current, power factor, power output, speed, torque, and efficiency. The specific calculations will require the use of motor equivalent circuit analysis and electrical formulas to find these values assuming a single-phase motor operation at the rated voltage and frequency.

User FireEmerald
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