Final answer:
To find the values of H0 and a in the electromagnetic waves H(R,t)=aϕH₀, cos(wt - kR) (A/m), H₁(R,t) = aϕ10⁻³ sin(wt-kR) (A/m), and H₂(R,t) = aϕ3x10⁻³ sin(wt- kR + a) (A/m), we can determine that H₀ = aϕ10⁻³ and a = 3x10⁻³.
Step-by-step explanation:
Given the electric field H(R, t) = aϕH₀, cos(wt - kR) (A/m), magnetic field strength H₁(R, t) = aϕ10⁻³ sin(wt - kR) (A/m), and H₂(R, t) = aϕ3x10⁻³ sin(wt - kR + a) (A/m), we need to find the values of H₀ and a.
From the given information, we can determine that H₀ = H₁ + H₂. Therefore, H₀ = aϕ10⁻³ sin(wt - kR) + aϕ3x10⁻³ sin(wt - kR + a).
By comparing the given equation with the derived equation, we can conclude that H₀ = aϕ10⁻³ and a = 3x10⁻³.