Question

Solve each inequality
`- 3e - 10 \leqslant - 14`
`(c)/(2) + 8 \ \textgreater \ 11`
`15 \leqslant 3 - 4s`
`(3)/(4)j + 1 \ \textgreater \ 4`

Answer 1

1.

`\begin{gathered} -3e-10\le-14 \\ -3e\le-14+10 \\ -e\le(-4)/(3) \end{gathered}`

is you remove a negative sign you have to rotate the symbol of < or >

`e\ge(4)/(3)`

2.

`\begin{gathered} (c)/(2)+8>11 \\ (c)/(2)>11-8 \\ c>(3)/(2) \end{gathered}`

3.

`\begin{gathered} 15\le3-4s \\ 15-3\le-4s \\ 12\le-4s \\ (12)/(4)\le-s \\ 3\ge s \\ s\le3 \end{gathered}`

4.

`\begin{gathered} (3)/(4)j+1>4 \\ (3)/(4)j>4-1 \\ (1)/(4)j>(3)/(3) \\ j>4*1 \\ j>4 \end{gathered}`