Question

What is the equation of the line that passes through the point (-3,1) and has aslope of 2/3?

Answer 1

The point-slope form of the linear equation is

`y-b=m(x-a)`

So, we need to replace the poin and the slope in the previous formula

`\begin{gathered} y-1=(2)/(3)(x-(-3)) \\ y-1=(2)/(3)x+(2)/(3)3 \\ y=(2)/(3)x+2+1 \\ \end{gathered}`

Then, the answer is

`y=(2)/(3)x+3`

or

`2x-3y+9=0`

Both equations are correct.