Final answer:
In this case, we have a quadratic equation with coefficients a = 1, b = 0.0211, and c = -0.0211. Using the quadratic formula, we can find the solutions for X as -0.1565 and 0.1354.
Step-by-step explanation:
In this case, a = 1, b = 0.0211, and c = -0.0211. Substituting the appropriate values for a, b, and c, we can find the values of X.
We can use the quadratic formula to find the solutions:
X = (-b ± √(b^2 - 4ac)) / (2a)
Substituting the values, we have:
X = (-(0.0211) ± √((0.0211)^2 - 4(1)(-0.0211))) / (2(1))
Simplifying the equation:
X = (-0.0211 ± √(0.00044421 + 0.08484)) / 2
X = (-0.0211 ± √0.08528421) / 2
X = (-0.0211 ± 0.2919) / 2
So, the solutions for X are:
X ≈ -0.1565, 0.1354