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You are provided two bases:

Vᴸᴸᵦₐₛₑ= 220kV, S³⁰ᵦₐₛₑ= 1MVA.
Calculate the current and Y-connected impedance bases; IBase ​,ZBaseY​, Also calculate the actual values of current and Y-connected load that correspond to 50% per unit.

User Moritzrupp
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1 Answer

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Final answer:

The base current (IBase) is calculated to be 2.624 A, and the Y-connected base impedance (ZBaseY) is 48.4 Ohms. For 50% per unit, the actual current is 1.312 A, and the actual Y-connected impedance is 96.8 Ohms.

Step-by-step explanation:

The base current (IBase) can be calculated using the formula:

IBase = Sbase / (sqrt(3) × VLLbase)

Where Sbase is the apparent power base and VLLbase is the line-to-line voltage base.

Given Sbase = 1 MVA and VLLbase = 220 kV:

IBase = 1 MVA / (sqrt(3) × 220 kV) = 2.624 A (rounded to three decimal places).

The base Y-connected impedance (ZBaseY) is given by:

ZBaseY = VLLbase² / Sbase

ZBaseY = (220 kV)² / 1 MVA = 48.4 Ω (rounded to one decimal place).

Now, to calculate the actual values of current and Y-connected load corresponding to 50% per unit:

Actual Current = 50% of IBase = 0.5 × 2.624 A = 1.312 A

Actual Impedance = ZBaseY / 0.5 = 48.4 Ω / 0.5 = 96.8 Ω

User Mikesigs
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