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If the op amp's slew rate limit is 0.5 Volt per microsecond, and a 5 Vpp output is required, what is the maximum frequency permissible without slew rate limiting?

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Final answer:

The maximum frequency permissible without slew rate limiting is approximately 0.015915 MHz or 15.915 kHz.

Step-by-step explanation:

The slew rate of an operational amplifier (op amp) limits how fast it can change its output voltage. In this case, the slew rate limit is 0.5 Volt per microsecond. To determine the maximum frequency without slew rate limiting, we can calculate the rate of change of the output voltage when it reaches its maximum value.

Given that the output voltage amplitude is 5 Vpp (peak-to-peak) and the slew rate limit is 0.5 V/µs, the rate of change of the voltage can be calculated using the formula:

slew rate = 2 * π * frequency * Vpp

Rearranging the formula to solve for the frequency, we get:

frequency = slew rate / (2 * π * Vpp)

Substituting the given values, we have:

frequency = 0.5 V/µs / (2 * π * 5 V)

frequency ≈ 0.015915 MHz

Therefore, the maximum frequency permissible without slew rate limiting is approximately 0.015915 MHz or 15.915 kHz.

User Dallin
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