Final answer:
Becky and Erin's performance on their respective tests is best compared using Z-scores. Becky's Z-score was 1.90 while Erin's was 1.75, indicating that Becky scored relatively better on her test, being further above the mean than Erin.
Step-by-step explanation:
To settle the argument regarding which student did better on their respective test comparing Becky's score on Mr. Foster's test with Erin's score on Ms. Helmer's test, we need to calculate their Z-scores.
The Z-score is a statistical measure that tells us how many standard deviations an individual's score is from the mean of the group. The formula for calculating a Z-score is Z = (X - μ) / σ, where X is the score, μ (mu) is the mean, and σ (sigma) is the standard deviation.
For Becky:
Z = (78 - 70) / 4.2
Z = 8 / 4.2
Z = 1.90
For Erin:
Z = (45 - 35) / 5.7
Z = 10 / 5.7
Z = 1.75
Comparing the Z-scores, Becky's score is higher, meaning she scored more standard deviations above the mean than Erin did. Therefore, option A is the most correct: Becky has a Z-score of 1.90 while Erin has a Z-score of 1.75. Becky scored more standard deviations above the mean, therefore she did better on the test.