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Vertically into the air from a 9-foot-ta tionh (t)=-16t²+v₀t+h₀, where

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Final answer:

The question is about the kinematic equations used to analyze the vertical motion of a projected object in physics, specifically addressing equations for trajectory, maximum height, and velocity after a fall.

Step-by-step explanation:

The question seems to address the topic of vertical motion analysis using kinematic equations in the context of a physics problem at the high school level. When an object is projected vertically into the air, its motion can be described by kinematic equations which include the factors of initial velocity, acceleration due to gravity, and the initial position.

One important equation for analyzing vertical motion is y = yo + voyt + ½at², where y represents the final position, yo the initial position, voy the initial velocity in the y-direction, a the acceleration (in this case -9.80 m/s² due to gravity), and t being the time elapsed.

At the peak of its trajectory, the velocity in the y-direction (vy) is 0, and we can use the equation v² = voy² + 2g(y - yo) to calculate the maximum height (y) reached by the object. This equation is derived from the principle of conservation of energy, and in the context of fluids, it is referred to as Torricelli's theorem.

Finally, the equation v = √2g|h| + v0² is used to calculate the velocity of an object at a certain position y considering a height h that has been dropped with negligible air resistance.

User Mr Griever
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