Final answer:
To find the power delivered to a resistive load of 13.48Ω by a solar cell module at non-standard conditions, calculate the adjusted current and voltage, and then use Ohm's Law. The power delivered is approximately 7.54 watts.
Step-by-step explanation:
To calculate the power delivered to a resistive load by a solar cell module, we need to account for the change in operating conditions from the reference conditions. First, the change in insolation from 1000 W/m² to 750 W/m² will proportionally decrease the output current. The current under new insolation, I', can be calculated by multiplying the module's maximum power point current (Imp) by the ratio of the new insolation to the reference insolation:
I' = Imp × (New insolation / Reference insolation) = 1.0 A × (750 W/m² / 1000 W/m²) = 0.75 A
Next, we assess the impact of the change in temperature from the reference temperature of 20°C to the actual temperature of 15°C on the module's current and voltage. The temperature coefficient of current (μ I,s) and voltage (μ V,o) are used to calculate the adjustment for the current and voltage output, respectively:
ΔI = μ I,s × (T - Tref) = 0.0005 A/K × (15°C - 20°C) = -0.0025 A
ΔV = μ V,o × (T - Tref) = -0.05 V/K × (15°C - 20°C) = 0.25 V
The adjusted current and voltage at the cell's new operating conditions are:
Iadjusted = I' + ΔI = 0.75 A - 0.0025 A = 0.7475 A
Vadjusted = Vmp + ΔV = 12.5 V + 0.25 V = 12.75 V
Finally, we calculate the power delivered to a load of 13.48Ω using Ohm's Law (P = I²R), where R is the resistance, and I is the current through the resistor:
P = Iadjusted² × R = 0.7475 A² × 13.48Ω = 7.54 W
Therefore, the power delivered to a 13.48Ω resistive load is approximately 7.54 watts.