Question

If V₁=4 V \), what is the value of V₂ ?

Answer 1

The question lacks sufficient detail to solve for V₂. It mentions Ohm's law, suggesting it's a physics question related to electrical circuits, but without additional information or context, a precise calculation for V₂ cannot be made.

Step-by-step explanation:

The question provided seems incomplete and lacks enough details to provide a directly accurate answer for the value of V₂. The details given are disconnected and do not present a clear physical setup or complete formula that could be used to solve for V₂. However, based on Ohm's law and typical circuit analysis, if this were a question about electrical circuits, V₂ would typically refer to the voltage across a particular component in the circuit. For a series circuit, the voltages across individual resistors add up to the total voltage supplied. For a parallel circuit, the voltage across all resistors is the same and is equal to the total voltage supplied. Without more context or a clear connection between V₁ and V₂, a specific numerical answer for V₂ cannot be provided.

Answer 2

In this case, if V₁=4V, then the value of V₂ is 0.8V.

Step-by-step explanation:

To determine the value of V₂, we need to analyze the given circuit diagram and the information provided.

From the circuit diagram, we can see that there are resistors with values of 50 Ω, 50 Ω, and 25 Ω. Additionally, there is a voltage source V₁ with a value of 4V.

To find the value of V₂, we need to apply Ohm's Law and analyze the voltage division in the circuit.

Here are the steps to solve for V₂:

1. Identify the resistors connected in series and calculate their total resistance. In this case, the resistors with values of 50 Ω and 50 Ω are in series, so their total resistance is 100 Ω.

2. Calculate the voltage drop across the resistors in series. Since they have the same resistance, the voltage drop across each resistor will be equal.

Voltage drop across the 50 Ω resistor = (50 Ω / (50 Ω + 50 Ω)) * V₁ = 0.5 * 4V = 2V.

3. Apply voltage division to determine the voltage across the 25 Ω resistor. Voltage division states that the voltage across a resistor in a series circuit is proportional to its resistance.

Voltage across the 25 Ω resistor = (25 Ω / (100 Ω + 25 Ω)) * V₁ = (25 Ω / 125 Ω) * 4V = 0.2 * 4V = 0.8V.

Therefore, the value of V₂ is 0.8V.

Your question is incomplete, but most probably the full question was:

If V₁=4 V , what is the value of V₂ ?(Refer to the image of circuit below)