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A PAM wave is produced by the message

m(t)=2sin(2πfₘ​t)
Assume that the modulation frequency fm​=0.2 Hz, sampling period Ts​=1 s, and pulse duration (with rectangular pulse shape) T=0.4s
[infinity]
Plot the PAM wave (time-domain): s(t)=∑n=​m(nTₛ​)h(t−nTₛ​).
−[infinity]

1 Answer

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Final answer:

To plot the PAM wave in the time-domain, we need to calculate the value of s(t) at different time intervals using the formula s(t) = ∑m(nTs)h(t−nTs).

Step-by-step explanation:

A PAM wave is produced by the message m(t) = 2sin(2πfₘt). To plot the PAM wave in the time-domain, we need to calculate the value of s(t) at different time intervals. The sampling period, Ts, is 1s and the pulse duration, T, is 0.4s. We can use the formula s(t) = ∑m(nTs)h(t−nTs) to calculate the PAM wave at different time intervals.

For example, when t = 1s, we have s(1) = m(0)h(1) + m(1)h(0) + m(2)h(-1) + m(3)h(-2) + .... We can substitute the values of m(t) and h(t) into this equation to calculate the PAM wave at t = 1s. Similarly, we can calculate the PAM wave at t = 2s, t = 3s, t = 4s, and t = 5s using the same formula.

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