Question

Calculate the amplitude of the magnetic field intensity of the coaxial cable with the following properties:

- the inner conductor radius is 0.5 cm
- the outer conductor lies between 1 cm to 1.5 cm away from the center.
- the total current inside the inner conductor is 5 A
Calculate H at the point 1.04 cm away form the center

Answer 1

The amplitude of the magnetic field intensity at a point 1.04 cm away from the center of a coaxial cable with a 5 A current in the inner conductor is approximately 76.4 A/m.

Step-by-step explanation:

To calculate the amplitude of the magnetic field intensity (H) at a point 1.04 cm away from the center of a coaxial cable, we can use Ampère's law. Given the total current inside the inner conductor is 5 A and the point of interest lies outside the inner conductor but within the outer conductor, the magnetic field intensity can be found using the formula H = I /(2πr), where I is the current and r is the radial distance from the center.

Plugging in the values, we have H = 5 A / (2π * 1.04 * 10^-2 m) = 5 / (0.06544) A/m ≈ 76.4 A/m.

The amplitude of the magnetic field intensity at a point 1.04 cm from the center is approximately 76.4 A/m.