Question

How do the expressions 5f²−2e and 6(e+f)f compare when e=7 and f=2?

Answer 1

After substituting e=7 and f=2 into the expressions 5f²−2e and 6(e+f)f, the first expression evaluates to 6, and the second expression evaluates to 108.

Step-by-step explanation:

The question asks how the expressions 5f²−2e and 6(e+f)f compare when e=7 and f=2. To answer this, we can substitute the given values into each expression.

For the first expression, 5f²−2e, when f=2 and e=7, it becomes:

• 5(2)^2 - 2(7)
• 5(4) - 14
• 20 - 14 = 6

For the second expression, 6(e+f)f, when using the same values for e and f, it becomes:

• 6(7+2)(2)
• 6(9)(2)
• 54(2)
• 108

The first expression yields a value of 6, while the second expression yields a value of 108.