Question

A particle is launched horizontally from the top of a vertical cliff with a speed of 25 m/s, and the cliff has a height of 80 m, find the time of flight for the particle?

Answer 1

The time of flight for the horizontally launched particle is 3.2 seconds.

Step-by-step explanation:

The time of flight for a horizontally launched particle can be found using the formula:

t = d / v

where t is the time of flight, d is the horizontal distance traveled, and v is the horizontal velocity. Since the particle is launched horizontally, the horizontal distance traveled is equal to the horizontal velocity multiplied by the time of flight. The horizontal velocity is constant, so we can calculate it using the initial horizontal velocity:

v = v0x

where v0x is the initial horizontal velocity. In this case, the initial horizontal velocity is equal to the initial speed of the particle, which is 25 m/s. Therefore, v0x = 25 m/s.

Now we can calculate the time of flight:

t = d / v0x

Since the cliff has a height of 80 m and the particle is launched horizontally, the horizontal distance traveled is equal to the horizontal velocity multiplied by the time of flight. Substituting the given values into the formula:

t = d / v0x = 80 m / 25 m/s = 3.2 s