Question

A technician prepared 350 mL solution by dissolving 24.5 g Potassium hydroxide KOH, in water. Calculate the normality of the solution. (Atomic masses are: K = 39 amu, 0 = 16 amu, H

= 1 amu)

Answer 1

To calculate the normality of the solution, divide the number of moles of potassium hydroxide by the volume of the solution in liters. The normality of the solution is 10.4 N.

Step-by-step explanation:

To calculate the normality of the solution, we need to determine the number of moles of potassium hydroxide (KOH) and divide it by the volume of the solution in liters.

First, let's calculate the number of moles of KOH:

Mass of KOH = 24.5 g

Molar mass of KOH = (39 g/mol + 16 g/mol + 1 g/mol) = 56 g/mol

Number of moles of KOH = mass of KOH / molar mass of KOH = 24.5 g / 56 g/mol

Next, let's convert the volume of the solution to liters:

Volume of solution = 350 mL = 0.35 L

Finally, we can calculate the normality of the solution:

Normality = number of moles of KOH / volume of solution

Normality = (24.5 g / 56 g/mol) / 0.35 L

Normality = 10.4 N