Final answer:
The equation relating atomic fluorine concentration to molecular fluorine concentration is based on the stoichiometry of the reaction F2 (g) = 2F(g), where the concentration of atomic fluorine is twice that of molecular fluorine at equilibrium. However, a detailed derivation requires the equilibrium constant expression, which is not provided in the question.
Step-by-step explanation:
To derive the equation relating atomic fluorine concentration to molecular fluorine concentration, we must consider the dissociation of molecular fluorine (F2) into its atomic form (F). Assuming the reaction F2 (g) = 2F(g) is fast and reaches equilibrium quickly, the concentration of atomic fluorine will be twice that of molecular fluorine due to the stoichiometry of the reaction. However, for a detailed derivation, we would typically rely on the equilibrium constant expression for the reaction which relates the concentrations of products and reactants at equilibrium.
Unfortunately, the provided information seems to be unrelated to the specific task of deriving an equation for fluorine concentration in chemical equilibrium. None of the mentioned equations, such as those concerning freezing point depression or fluid dynamics, directly apply to this task.